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8x^2+10x-7x=0
We add all the numbers together, and all the variables
8x^2+3x=0
a = 8; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·8·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*8}=\frac{-6}{16} =-3/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*8}=\frac{0}{16} =0 $
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